Find the value of $x$ .

50^{o}

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60^{o}

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40^{o}

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52^{o}

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Solution

The correct option is A $50^{o}$
We know the sum of all exterior angles of the polygon is $360^{o}$ .
So, adding all angles of the above polygon, we will get
$x + x + 50^{o} + x - 10^{o} + x + 60^{o} + x + 10^{o} = 360^{o}$
$5 x + 110^{o} = 360^{o}$
$5 x = 360^{o} - 110^{o}$
$5 x = 250^{o}$
$x = \frac{250^{o}}{5}$
$x = 50^{o}$

Hence, option $(a)$ correct.

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