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Question

Find the value of x,if a+7=0; b+10=0 and 12x2=axb.

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Solution

If a + 7 =0, then a = -7
and b + 10 =0, then b = – 10
Put these values of a and b in the given equation
12 x squared equals left parenthesis negative 7 right parenthesis x minus left parenthesis negative 10 right parenthesis 12 x squared plus 7 x minus 10 equals 0 12 x squared plus 15 x minus 8 x minus 10 equals 0 3 x left parenthesis 4 x plus 5 right parenthesis minus 2 left parenthesis 4 x plus 5 right parenthesis equals 0 left parenthesis 4 x plus 5 right parenthesis left parenthesis 3 x minus 2 right parenthesis equals 0 i f space 4 x plus 5 equals 0 space space space space space o r space space space space space space 3 x minus 2 equals 0 x equals fraction numerator negative 5 over denominator 4 end fraction space space space space space space space space space space space space space o r space space space space space space x equals 2 over 3

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