Find the value of x if $x^{2} - 4 (x | + 3 = 0$

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-1

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-3

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Solution

The correct options are
A
1

B
-1

C
3

D
-3

$x^{2} - 4 (x | + 3 = 0$ or $(x^{2} ∣ ∣ - 4 (x | + 3 = 0$

[we will consider it as quadratic in |x|]

(|x| - 3) (|x| - 1) = 0

$\Rightarrow$ |x| = 3 or |x| = 1
$x = \pm 3$ or $x = \pm 1$

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Similar questions

Find the value of x if $x^{2} - 4 (x | + 3 = 0$

x :

x^{2} - 4 x + 4 = 0

x^{2} - 5 x - 6 > 0

x^{2} - 4 x + 3 \leq 0

(x^{2} + \frac{1}{x^{2}}) - 4 (x + \frac{1}{x}) + 6 = 0

\frac{1}{x} + \frac{x}{2}

4 x + 3

x

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