Find the volume of : [2 MARKS]

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Solution

Concept: 1 Mark
Application: 1 Mark

Volume = volume cylinder + volume cone

$= π r^{2} h + \frac{1}{3} π r^{2} h$

$= π (5)^{2} (20) + \frac{1}{3} π (5)^{2} (A B)$

$A B^{2} = A C^{2} - B C^{2}$ (Using Pythagoras Theorem)

$A B^{2} = 89 - 5^{2}$

$A B = 8 c m$

$= π (5)^{2} 20 + \frac{1}{3} π (5)^{2} 8$

$= 500 π + 200 \frac{π}{3}$

$= (\frac{1700}{3}) π$

$= 1780.24 c m^{3}$

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Find the volume of : [2 MARKS]

Concept: 1 Mark Application: 1 Mark Volume = volume cylinder + volume cone =πr2h+13πr2h =π(5)2(20)+13π(5)2(AB) AB2=AC2–BC2 (Using Pythagoras Theorem) AB2=89–52 AB=8cm =π(5)220+13π(5)28 =500π+200π3 =(17003)π =1780.24 cm3