Question

Find the zero of the polynomial:
(i) $p\left(x\right)=x-5$
(ii) $q\left(x\right)=x+4$
(iii) $r\left(x\right)=2x+5$
(iv) $f\left(x\right)=3x+1$
(v) $g\left(x\right)=5-4x$
(vi) $h\left(x\right)=6x-2$
(vii) $p\left(x\right)=ax+b,a\ne 0$
(viii) $q\left(x\right)=4x$

Answer 1

$\left(i\right)p\left(x\right)=x-5x-5=0x=5\text{zero of the polynomial}=5$

$\left(ii\right)q\left(x\right)=x+4x+4=0x=-4\text{zero of the polynomial}=-4$

$\left(iii\right)r\left(x\right)=2x+52x+5=0x=\frac{-5}{2}\text{zero of the polynomial}=\frac{-5}{2}$

$\left(iv\right)f\left(x\right)=3x+13x+1=0x=\frac{-1}{3}\text{zero of the polynomial}=\frac{-1}{3}$

$\left(v\right)g\left(x\right)=5-4x5-4x=0x=\frac{4}{5}\text{zero of the polynomial}=\frac{4}{5}$

$\left(vi\right)h\left(x\right)=6x-26x-2=0x=x=\frac{2}{6}=\frac{1}{3}\text{zero of the polynomial}=\frac{1}{3}$

$\left(vii\right)p\left(x\right)=ax+b,a\ne ax+b=0x=\frac{-b}{a}\text{zero of the polynomial}=\frac{-b}{a}$

$\left(viii\right)q\left(x\right)=4x4x=0x=0\text{zero of the polynomial}=0$