Find two numbers such that the larger number added to three times the smaller number gives 7 and twice the larger number added to the smaller number gives 9.
1, 4
Let the larger number be x and the smaller number be y.
x + 3y = 7 …(i)
2x + y = 9 …(ii)
On multiplying (i) by 2 and (ii) by 1, we get
2x+6y=14
2x+y=9
Solving the above two equations, we get
5y = 5
Or y = 55 = 1
On substituting value of y in (i), we get
x + 3×1 = 7
or x + 3 = 7
or x = 7 – 3 = 4
∴ Larger number is 4 and smaller number is 1.