Find x and y in $4 x + (3 x - y) i = 8 + 11 i,$

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Solution

Consider the given equation.

$4 x + (3 x - y) i = 8 + 11 i$ …….. (1)

On comparing real part and imaginary part, we get

$4 x = 8$

$x = 2$

And

$3 x - y = 11$

$3 \times 2 - y = 11$

$6 - y = 11$

$y = - 5$

Hence, the value of $x$ is $2$ and $y$ is $- 5$ .

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Similar questions

(x^{4} + 2 x i) - (3 x^{2} + y i) = (1 + 2 y i)

x + y

4 x + 3 y = 8

3 x + 4 y = 20

y = \sqrt{\frac{3^{x} - 4^{x}}{2 x^{2} - x - 8}} .

(x^{4} + 2 x i) - (3 x^{2} + y i) = (3 - 5 i) + (1 + 2 y i)

Solve for X and y
$4 x + \frac{y}{3} = \frac{8}{3}$
$\frac{x}{2} + 3 \frac{y}{4} = \frac{- 5}{2}$

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