Find $x$ if $9, x, 14, 18, x, x, 8, 10$ and $4$ have a mean of $11$ .

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Solution

Given $9, x, 14, 18, x, x, 8, 10$ and $4$ have a mean of $11$ .
Now,
$\frac{9 + x + 14 + 18 + x + x + 8 + 10 + 4}{9} = 11$ [ As there are $9$ terms]
or, $\frac{63 + 3 x}{9} = 11$
or, $3 x = 99 - 63$
or, $3 x = 36$
or, $x = 12$ .

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