Five real numbers x1,x2,x3,x4,x5 are such that: √x1−1+2√x2−4+3√x3−9+4√x4−16+5√x5−25=x1+x2+x3+x4+x52The value of x1+x2+x3+x4+x52 is
If M is the mean of x1,x2,x3,x4,x5 and x6,prove that (x1−M)+(x2−M)+(x3−M)+(x4−M)+(x5−M)+(x6−M)=0
If x1,x2,x3,x4 are four positive real numbers such that x1+1x2=4, x2+1x3=1, x3+1x4=4 and x4+1x1=1, then