For a matrix A⎛⎜⎝100210321⎞⎟⎠, if U1,U2 and U3 are 3×1 column matrices satisfying AU1=⎛⎜⎝100⎞⎟⎠,AU2⎛⎜⎝230⎞⎟⎠,AU3=⎛⎜⎝231⎞⎟⎠ and U is 3×3 matrix whose columns are U1,U2 and U3 Then sum of the elements of U−1 is
A
6
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B
0(zero)
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C
1
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D
2/3
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Solution
The correct option is A0(zero) Let Ui=⎛⎜⎝aibici⎞⎟⎠i=1,2,3 AU1=⎛⎜⎝a12a1+b13a1+2b1+c1⎞⎟⎠=⎛⎜⎝100⎞⎟⎠, So a1=1,b1=−2,c1=1 AU2=⎛⎜⎝a22a2+b23a2+2b2+c2⎞⎟⎠=⎛⎜⎝230⎞⎟⎠, So, a2=2,b2=−1,c2=−4. Similarly, a3=2,b3=−1,c3=−3 So, U=⎛⎜⎝122−2−1−11−4−3⎞⎟⎠. So, sum of elements of U−1 is zero.