MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Half Wave Rectifier

for a value o...

Question

for a value of ω for which the current amplitude is 1/\sqrt2 times its maximum value .At this value the power dissipiated in the circuit becomes half .prove it

Open in App

Solution

Suggest Corrections

thumbs-up

4

Similar questions

Q. A series LCR circuit with L = 0.12 H, C = 480 nF, R = 23 W is connected to a 230 V variable frequency supply. (a) What is the source frequency for which current amplitude is maximum. Obtain this maximum value. (b) What is the source frequency for which average power absorbed by the circuit is maximum. Obtain the value of this maximum power. (c) For which frequencies of the source is the power transferred to the circuit half the power at resonant frequency? What is the current amplitude at these frequencies? (d) What is the Q-factor of the given circuit?

Q. In damped oscillations, if the amplitude becomes half of its maximum value in

1 s

2 s

amplitude will be
(

A_{o}

is initial amplitude)

Q. An LR circuit having a time constant of 50 ms is connected with an ideal battery of emf ε. find the time elapsed before (a) the current reaches half its maximum value, (b) the power dissipated in heat reaches half its maximum value and (c) the magnetic field energy stored in the circuit reaches half its maximum value.

Q. In damped oscillations, if the amplitude becomes half of its maximum value in

1 s

2 s

amplitude will be
(

A_{o}

is initial amplitude)

Q. If the effective voltage of the AC source is 200 V and it’s frequency is variable for the circuit shown, then

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Half Wave Rectifier

PHYSICS

Watch in App

explore_more_icon

Explore more

Half Wave Rectifier

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon