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Question

For SO2Cl2(g)SO2(g)+Cl2(g), Pressure of SO2Cl2 changed from 5 atm to 4 atm in 10 min. Then, pressure of SO2Cl2 at the end of 30 minutes will be (in atm):

A
2.56
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B
3.56
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C
4.56
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D
5.56
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Solution

The correct option is D 2.56

Here the given reaction is:

SO2Cl2(g)SO2(g)+Cl2(g)

Initial pressure of SO2Cl2=5atm.

And pressure left after 10 minutes =[ax]=A=4atm.

Hence by rate law

For first order reaction

Rate constant (K) =2.303tlog[A0][A]

K=2.30310log540.2303[log5log4]

=2.2303[0.69800.6020]

K=0.0223

Now,

t=30min

Concentration of SO2Cl2 at the end of this time

K=2.303tlog[A0][A]0.0223=2.30330log5[A]

0.0223×302.303=log5logA

0.2907=log5logA

logA=0.69890.29070.40[A]=100.402.56


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