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Question

, for some constant a and b .

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Solution

Let, y=cos( acosx+bsinx )

Differentiate both sides with respect to x,

dy dx = d dx { cos( acosx+bsinx ) } =sin( acosx+bsinx )× d dx ( acosx+bsinx ) =sin( acosx+bsinx )[ a( sinx )+bcosx ] =( asinxbsinx )sin( acosx+bsinx )

Thus, the derivative of the given function is ( asinxbsinx )sin( acosx+bsinx ).


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