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Question

For the given graph of y=tan2x; xR
Select the correct statements.


A
Period: π/2
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B
Period: π/4
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C
Domain: R(2n+1)π/4; nZ
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D
Domain: R
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Solution

The correct option is C Domain: R(2n+1)π/4; nZ
Given the graph of tan2x xR


As clear from the graph, tanx is not defined at values which are odd multiples of π/4
So, it's domain will be:
R(2n+1)π2 nZ

Now, coming to periodicity, we can find it either from the graph itself or by using the expression.

1st method:

As per the graph of tan2x the value is getting repeated after every 3π4π4=π2


2nd Method:

Now, using the fact that if f(x) has a period T,
then f(ax+b) will have a period T|a|.

Using the same concept. we know tanx has a fundamental period π
tan2x will have a fundamental period π/2

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