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Dehydrohalogenation of Dihalides

For the given...

Question

For the given reaction the major product 'B' is :

C H_{2} = C H - C H = C H_{2}

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C H_{3} - C \equiv C - C H_{3}

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C H_{3} - C H_{2} - C \equiv C H

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C H_{3} - C H = C = C H_{2}

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Solution

The correct option is B $C H_{3} - C \equiv C - C H_{3}$
Alkenes react with $B r_{2}$ in presence of $C C l_{4}$ as a solvent forms a vicinal dihalide.
$Vicinal dihalide Alc. KOH - ----- \to Δ Alkenyl Halide N a^{+} N H_{2}^{-} - ----- \to Alkyne + N a X + N H_{3}$

So, (b) is correct

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Similar questions

C H_{2} = C H - C | H - C H_{2} C H_{3} C | C l = C H_{2}

C H_{3} - C H = C H - C H_{3} H_{3} O^{+} - -- \to C H_{3} - C H_{2} - O H | C H - C H_{3}

C H_{3} - C | C H_{3} H - C H_{2} - C H_{2} - O H

C H_{3} - O H | C | C H_{3} - C H_{2} - C H_{3}

C H_{3} C H_{3} | C H - O H | C H - C H_{3}

A, B, C

S_{N} 2

c o n c . H C l :

(a) C H_{3} - C H_{2} - O H A n h y Z n C l_{2} / △ - -------- \to C H_{3} - C H_{2} - C l

(b) C H_{3} - C H_{3} | C | C H_{3} - C H_{2} O H A n h y Z n C l_{2} / △ - -------- \to C H_{3} - C H_{1} | C | C H_{3} - C H_{2} - C H_{3}

(c) C H_{3} - O H | C | C H_{3} - C H_{3} A n h y Z n C l_{2} / △ - -------- \to C H_{3} - C l | C | C H_{3} - C H_{3}

(d) C H_{2} = C H - C H_{2} - O H A n h y Z n C l_{2} / △ - -------- \to C H_{2} = C H - C H_{2} - C l

H_{3} C - C H_{2} - C | H - C H_{2} C H_{3} C H_{2} - C | H C H_{3} - C H_{2} C H_{3}

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