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Question

For the given signal h(t)


The Fourier transform is/are

A
2Sa(ω)+ejωSa(ω)+ejωSa(ω)
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B
1jω[e+2jωe2jω+ejωejω]
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C
2Sa(ω)+2ejωSa(ω)2ejωSa(ω)
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D
4Sa(2ω)+2Sa(ω)
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Solution

The correct option is D 4Sa(2ω)+2Sa(ω)


option (a)
h(t)=rect(t4)+rect(t2)

H(ω)=4Sa(ω×42)+2Sa(ω×22)

H(ω)=4Sa(2ω)+2Sa(ω)

option (c)
h(t)=rect(t4)+rect(t2)

=12[sgn(t+2)sgn(t2)+sgn(t+1)sgn(t1)]

=12[e2jω×2jωe2jω×2jω+ejω×2jω]

=1jω[e2jωe2jω+ejωejω]

Only options A,C are correct

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