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Question

For the parabola x2=8y y=2x+A,y=x+B,y=3x+C,y=4x+D are the tangents of the parabola then the arrangement of A,B,C,D in the descending order is

A
A,B,C,D
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B
C,B,A,D
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C
B,A,C,D
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D
C,A,D,B
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Solution

The correct option is C B,A,C,D

Tangent of parabola is
y=mx+am

A=22=1

B=21=2

C=23=23

D=24=12

Order is B,A,C,D.


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