For x = 3, y = 2, u = -9, v = 13 the point (x+y, u+v) lies in which quadrant?

III quadrant

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II quadrant

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IV quadrant

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I quadrant

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Solution

The correct option is D
I quadrant

Abscissa is x + y = 3 + 2 = 5

Ordinate is u + v = -9 + 13 = 4

The point is (5, 4).

Since both coordinates are positive the point lies in I quadrant.

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Similar questions

x = 2, y = - 1, u = 3, v = 2

(x \times y, u \times v)

\frac{u}{v} = \frac{w}{x} = \frac{y}{z}

{[\frac{u w^{2} + 7 u y^{2} + 3 y u^{2}}{u x^{2} + 7 x^{2} + 3 z v^{2}}]}^{\frac{1}{3}} .

(x - 1) (y - 2) = 4

x^{2} + y^{2} - 7 x - 9 y + c = 0

(3, 4), (5, 3), (2, 6)

P (u, v)

9 (u + v)

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