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Question

Four blocks of masses M1,M2,M3 and M4 are placed on a smooth horizontal surface along a straight line as shown above. It is given that M1>>M2>>M3>>M4. All the blocks are initially at rest. M1 is given initial velocity v0 towards right such that it will collide with M2. Consider all collisions to be perfectly elastic. The speed of M4 after all collision are over is

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A
v0
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B
4 v0
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C
8 v0
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D
16 v0
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Solution

The correct option is B 8 v0
M1 is very large as compared to M2. Hence for collision between M1 and M2,M1 can be considered equivalent to a wall and M2 as a small block. Thus the velocity of M2 will be 2v0 after collision with M1.
Similarly after collision between M2 and M3, the velocity of M3 will be 2(2v0). In sequence, the velocity of M4 shall be 2(2(2v0))=8v0 after collision with M3.

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