1-1 - tan2 - - 1-1 - cot2 - -

We know that,1 + tan^2 θ = sec^2 θ and 1 + cot^2 θ = cosec^2 θ 1/1 + tan^2 θ + 1/1 + cot^2 θ=1/sec^2 θ + 1/cosec^2 θ = cos^2 θ + sin^2 θ = 1 ...

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Visualisation of Trigonometric Ratios Using a Unit Circle

1/1 + tan2 θ ...

Question

$\frac{1}{1 + t a n^{2} θ} + \frac{1}{1 + c o t^{2} θ} =$

-1

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\frac{1 + t a n^{2} Θ}{1 + c o t^{2} Θ} = (\frac{1 - t a n Θ}{1 - c o t Θ})^{2} = t a n^{2} Θ .

\sqrt{1 + t a n^{2} θ} \sqrt{1 + c o t^{2} θ} \sqrt{1 - c o s^{2} θ} \sqrt{1 - s i n^{2} θ} =

{cos}^{4} θ + {cos}^{2} θ = 1

s e c^{4} θ - s e c^{2} θ = 1

{cot}^{4} θ - c o t^{2} θ = 1

t a n^{4} θ - t a n^{2} θ = 1

$t a n^{2} θ + c o t^{2} θ + 2 =$

1 + {c o t}^{2} θ =

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