Lowest term of 16/24 =2/3 ( Divide both terms by their HCF 8)Lowest term of 30/20 =3/2 ( Divide both terms by their HCF 10)Since both are not equal.Hence, it is ...

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Standard VI

Mathematics

Lowest Form

16/24=30/20

Question

$\frac{16}{24} = \frac{30}{20}$

True

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False

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Solution

The correct option is B False
Lowest term of $\frac{16}{24}$ $= \frac{2}{3}$ ( Divide both terms by their HCF $8$ )
Lowest term of $\frac{30}{20}$ $= \frac{3}{2}$ ( Divide both terms by their HCF $10$ )
Since both are not equal.
Hence, it is false that $\frac{16}{24} = \frac{30}{20}$

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Q. The least integer greater than

{log}_{2} 15 \cdot {log}_{\frac{1}{6}} 2 \cdot {log}_{3} \frac{1}{6}

is equal to

Q. The smallest integer satisfying the equation

∣ ∣ ∣ {log}_{\frac{1}{6}} x - 1 ∣ ∣ ∣ + 2 = ∣ ∣ ∣ {log}_{\frac{1}{6}} x - 3 ∣ ∣ ∣

\frac{22}{6} - \frac{20}{24} = ?

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1624=3020

The correct option is B FalseLowest term of 1624 =23 ( Divide both terms by their HCF 8)Lowest term of 3020 =32 ( Divide both terms by their HCF 10)Since both are not equal.Hence, it is false that 1624=3020

$\frac{16}{24} = \frac{30}{20}$

The correct option is B False
Lowest term of $\frac{16}{24}$ $= \frac{2}{3}$ ( Divide both terms by their HCF $8$ )
Lowest term of $\frac{30}{20}$ $= \frac{3}{2}$ ( Divide both terms by their HCF $10$ )
Since both are not equal.
Hence, it is false that $\frac{16}{24} = \frac{30}{20}$