2(x−1)5≤3(2+x)7
2(x−1)5≤3(2+x)7⇒7(2(x−1))≤5(3(2+x))⇒ 14(x−1)≤15(2+x)⇒ 14x−14≤30+15x⇒ 14x−15x≤30+14⇒−x≤44⇒x≥−44∴ The solution set is [−44,∞]
Factorize 2x2−7x+5=0