Write in factorised form: 2x2−5x+2=0
Given 2x2−5x+2=0Since, LCM of x2 and x is x2 (2−5x+2x2)x2=0⇒2x2−5x+2=0⇒2x2−4x−x+2=0⇒2x(x−2)−1(x−2)=0∴ (x−2)(2x−1)=0