$\frac{6}{11}$ ___ $\frac{16}{33}$

$>$

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Solution

The correct option is A
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We have to compare two fractions.

First of all make their denominators same which is equal to the L.C.M of $11$ and $33$ , i.e., $33$

$\Rightarrow \frac{6}{11} = \frac{6 \times 3}{11 \times 3} = \frac{18}{33}$

Now, we can compare $\frac{18}{33}$ and $\frac{16}{33}$ as their denominators are same.

Comparing numerators, $18 > 16$

$\Rightarrow \frac{18}{33} > \frac{16}{33}$

$\Rightarrow \frac{6}{11} > \frac{16}{33}$

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\sqrt{16 + 2 \sqrt{6} + 2 \sqrt{22} + 2 \sqrt{33}} =

cos \frac{π}{33} cos \frac{2 π}{33} cos \frac{4 π}{33} cos \frac{8 π}{33} cos \frac{11 π}{33} cos \frac{16 π}{33}

\begin{matrix} 8 & 4 & (28) 12 & 3 & (33) 11 & 6 & (. . . .) \end{matrix}

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