The simplest form of $\frac{\sqrt[4]{243}}{\sqrt[4]{3}}$ is

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Given: $\frac{\sqrt[4]{243}}{\sqrt[4]{3}}$

$= \sqrt[4]{\frac{243}{3}}$ [Since, $\frac{\sqrt{a}}{\sqrt{b}} = \sqrt{\frac{a}{b}}$ ]
$= \sqrt[4]{81}$
$= (3^{4})^{\frac{1}{4}}$ [Since, $(a^{m})^{n} = a^{m \times n}$ ]
$= 3$
Hence, the correct option is A. ( $3$ )

Suggest Corrections

Similar questions

\frac{4}{(216)^{- \frac{2}{3}}} + \frac{1}{(256)^{- \frac{4}{4}}} + \frac{4}{(243)^{- \frac{1}{5}}}

Simplify $\frac{4}{{(216)}^{- 2 / 3}} + \frac{1}{{(256)}^{- 3 / 4}} + \frac{2}{{(243)}^{- 1 / 5}}$

\frac{(25)^{3 / 2} \times (243)^{3 / 5}}{(16)^{5 / 4} \times 8^{4 / 3}}

\frac{4}{(216)^{- \frac{2}{3}}} + \frac{1}{(256)^{- \frac{3}{4}}} + \frac{2}{(243)^{- \frac{1}{5}}}

\frac{4}{216^{\frac{- 2}{3}}}

\frac{1}{256^{\frac{- 3}{4}}}

\frac{2}{243^{\frac{- 1}{5}}}

Join BYJU'S Learning Program