X - a - x - b - x - c -1 - F ind the value of x-A- abc -a-b-cB- abc -a b-b c-c aC- a -a b-b c-c aD- a b-b c-c a -a-b-c

The correct option is B (abc) / (ab + bc + ca ) x/a+x/b+x/c=1 ⇒bcx+acx+abx/abc=1 ⇒ x(bc+ac+ab)=abc ⇒ x= abc/ab+bc+ca ...

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A.M Greater than or Equal to G.M

x / a + x / b...

Question

$\frac{x}{a} + \frac{x}{b} + \frac{x}{c} = 1. F i n d t h e v a l u e o f x .$

(abc) / (a + b + c)

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(abc) / (ab + bc + ca )

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a / ( ab + bc + ca )

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(ab + bc + ca ) / ( a + b + c )

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$Find x : \frac{x - b - c}{a} + \frac{x - c - a}{b} + \frac{x - a - b}{c} = 3, if \frac{1}{a} + \frac{1}{b} + \frac{1}{c} \neq 0$

a^{3} + b^{3} + c^{3} - 3 a b c

In Triangle ABC, which of the following is not true:

(a) AB + BC + CA = 0
(b) AB + BC - AC = 0
(c) AB + BC - CA = 0
(d) AB - CB + CA = 0

x : y : 1 = t^{3} : t^{2} - 3 : t - 1

∣ ∣ ∣ ∣ ∣ \begin{matrix} b c - a^{2} & c a - b^{2} & a b - c^{2} - b c + c a + c b & b c - c a + a b & b c + c a - a b (a + b) (a + c) & (b + c) (b + a) & (c + a) (c + b) \end{matrix} ∣ ∣ ∣ ∣ ∣ = 3 (b - c) (c - a) (a - b) (a + b + c) (b c + c a + a b)

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