Give a balanced equation for the reaction: Zinc sulphide and dilute sulphuric acid.

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Solution

The reaction between Zinc sulphide $(Z n S)$ and dilute sulphuric acid is -

$Z n S + dil. H_{2} S O_{4} \to Z n S O_{4} + H_{2} S$

Thus, sulphuric acid liberates hydrogen sulphide $(H_{2} S)$ when it reacts with metal sulphides.

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Conservation of Mass

Standard X Chemistry

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Give a balanced equation for the reaction: Zinc sulphide and dilute sulphuric acid.

The reaction between Zinc sulphide (ZnS) and dilute sulphuric acid is - ZnS+ dil.H2SO4→ZnSO4+H2S Thus, sulphuric acid liberates hydrogen sulphide (H2S) when it reacts with metal sulphides.

The reaction between Zinc sulphide $(Z n S)$ and dilute sulphuric acid is -

$Z n S + dil. H_{2} S O_{4} \to Z n S O_{4} + H_{2} S$

Thus, sulphuric acid liberates hydrogen sulphide $(H_{2} S)$ when it reacts with metal sulphides.