Question

Given $A=B^2+\sqrt{\frac{9}{c}}$, then C is equal to

• A. 9 / (A-B)²
• B. 81/ (A-B²)²
• C. (3/ (A-B²)) ²
• D. 3 / (A-B²)²
• E. None of these

Answer 1

The correct option is C

(3/ (A-B²)) ²

$A-B^2=\sqrt{\frac{9}{c}}\Rightarrow \frac{9}{c}={\left(A-B^2\right)}^2\Rightarrow C=\frac{9}{{\left(A-B^2\right)}^2}={\left(\frac{3}{A-B^2}\right)}^2$