Given c1:x2+y2−2x−2y+3=0 and c2:2x2+2y2−4x−4y+7=0 are
Center of a circle is given by the equation
ax2+ay2+2gx+2fy+c=0 as (−ga,−fa)
Center of C1=(11,11)=(1,1)
Center of C2=(22,22)=(1,1)
C1 and C2 have the same center
C1 and C2 are concentric