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Byju's Answer
Standard VIII
Mathematics
Union of Sets
Given, P = a,...
Question
Given,
P = {a, b, c, e},
Q = {b, c, d, f} and
R = {c, f, h, i, j}. The n
umber of elements in the set
P
∪
Q
∪
R
is
A
12
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B
11
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C
10
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D
9
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Solution
The correct option is
D
9
Given,
P
=
{
a
,
b
,
c
,
e
}
,
Q
=
{
b
,
c
,
d
,
f
}
and
R
=
{
c
,
f
,
h
,
i
,
j
}
P
∪
Q
∪
R
=
(
P
∪
Q
)
∪
R
=
(
(
a
,
b
,
c
,
e
)
∪
(
b
,
c
,
d
,
f
)
)
∪
(
c
,
f
,
h
,
i
,
j
)
=
(
a
,
b
,
c
,
d
,
e
,
f
,
h
,
i
,
j
)
Thus, we have 9 elements in union.
Suggest Corrections
0
Similar questions
Q.
Given,
P
=
{
a
,
b
,
c
,
e
}
,
Q
=
{
b
,
c
,
d
,
f
}
and
R
=
{
c
,
f
,
h
,
i
,
j
}
.
Number of elements of the set
P
∩
Q
∩
R
is
Q.
μ
= {a, b, c, d, e, f, g, h, i, j}
P = {a, b, c, e}.
Q = {b, c, d, f} and
R = {c, f, h, i, j}
Number of elements of the set
(
P
∩
Q
)
∪
(
P
∩
R
)
is
Q.
μ
= {a, b, c, d, e, f, g, h, i, j}
P = {a, b, c, e}.
Q = {b, c, d, f} and
R = {c, f, h, i, j}
Number of elements of the set
(
P
∩
Q
)
′
∪
R
is:
Q.
If
△
DEF
≅
△
PQR, then,
Q.
In the given figure, PSDA is a parallelogram in which PQ = QR = RS and AP || BQ || CR. Prove that ar (PQE) = ar (Δ CFD).