Given that 12S8s-6O2g- 4SO3g- - H0-1590kJ- The standard enthalpy of formation of SO3 is-

The correct option is C 397.5 KJ mol^ 1 Solution: (B) 397.5 kJ/mol Given: 12S_8_( s ) + 6 O_2_( g )⟶ 4 SO_3_( g ); ΔH = 1590 kJ ..... ( ...

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Question

Given that $\frac{1}{2} S_{8} (s) + 6 O_{2} (g) \to 4 S O_{3} (g); Δ H^{0} = - 1590 k J$ . The standard enthalpy of formation of $S O_{3}$ is:

- 1590 K J m o l^{- 1}

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- 397.5 K J m o l^{- 1}

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- 3.975 K J m o l^{- 1}

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+ 397.5 K J m o l^{- 1}

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