Given that E0Cu2+|Cu=0.34V;E0Ag+|Ag=0.80V:E0Mg3+|Mg=−2.37 and E0Al3+|Al=−1.66V in which of the following cells the standard free energy decreases is maximum:
A
Mg|Mg2+(1M)||Cu2+(1M)|Cu
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B
Mg|Mg2+(1M)||Ag+(1M)|Ag
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C
Ag|Ag+(1M)||Al3+(1M)|Al
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D
Cu|Cu2+(1M)||Ag+(1M)|Ag
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Solution
The correct option is DCu|Cu2+(1M)||Ag+(1M)|Ag
ΔG=−nFE0
Where ΔG=Standard free energy
n=No. of electron
F=96500
ΔGCu=−2×0.34×96500=−65620
ΔGAg=−1×0.80×96500=−77200
ΔGMg=−2×(−2.37)×96500=457410
ΔGAl=−3×(−1.66)×96500=480570
We find that ΔG decreases is maximum in case of Cu and Ag.