Given that $E^{0}$ values of $A g^{+} / A g, K^{+} / K, M g^{2 +} / M g$ and $C r^{3 +} / C r$ are $0.80 V, - 2.90 V, - 2.37 V$ and $- 0.74 V$ respectively. Which of the following orders regarding the reducing power of the metals is correct?

A g > C r > M g > K

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A g < C r < M g < K

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A g > C r > K > M g

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C r > A g > M g > K

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Solution

The correct option is B $A g < C r < M g < K$
More positive reduction potential means more easily an ion is reducible and more difficult is the oxidation of the corresponding atom. Reducing power of the metal means more easily the metals should be oxidisable. So, lesser the value of reduction potential, more is the reducing power. Hence $A g (0.80 V)$ has least reducing power whereas $K (- 2.90 V)$ with least reduction potential has maximum reducing power.
Hence, (b) is correct.

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Similar questions

Given the standard electrode potentials,

K⁺/K = −2.93V, Ag⁺/Ag = 0.80V,

Hg²⁺/Hg = 0.79V

Mg²⁺/Mg = −2.37 V, Cr³⁺/Cr = − 0.74V

Arrange these metals in their increasing order of reducing power.

Given the standard electrode potentials,
$K^{+} / K = - 2.93 V, A g^{+} / A g = 0.80 V, H g^{2 +} / H g$
$= 0.79 V$
$M g^{2 +} / M g = - 2.37 V . C r^{3 +} / C r = - 0.74 V$
Arrange these metals in their increasing order of reducing power.

Q. Given the standard reduction potentials,

E_{K^{+} / K}^{\circ} = - 2.93 V, E_{A g^{+} / A g}^{\circ} = + 0.80 V, E_{H g^{2 +} / H g}^{\circ} = 0.79 V

E_{M g^{2 +} / M g}^{\circ} = - 2.37 V, E_{C r^{3 +} / C r}^{\circ} = - 0.74 V

.
The correct increasing order of reducing power is:

Q. Which is the correct increasing order of reducing power of the given metals?
Standard electrode potentials:

K^{+} + e^{-} \to K; E^{0} = - 2.93 V A g^{+} + e^{-} \to A g; E^{0} = 0.80 V H g_{2}^{2 +} + e^{-} \to 2 H g; E^{0} = 0.79 V M g^{2 +} + e^{-} \to M g; E^{0} = - 2.37 V C r^{3 +} + e^{-} \to C r; E^{0} = - 0.74 V

Q. Given the standard electrode potentials,

K^{+} / K = - 2.93 V A g^{+} / A g = 0.80 V H g^{2 +} / H g = 0.79 V M g^{2 +} / M g = - 2.73 V C r^{3 +} / C r = - 0.74 V

The increasing order of reducing power is:

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Given that E0 values of Ag+/Ag,K+/K,Mg2+/Mg and Cr3+/Cr are 0.80 V,−2.90 V,−2.37 V and −0.74 V respectively. Which of the following orders regarding the reducing power of the metals is correct?

Given that $E^{0}$ values of $A g^{+} / A g, K^{+} / K, M g^{2 +} / M g$ and $C r^{3 +} / C r$ are $0.80 V, - 2.90 V, - 2.37 V$ and $- 0.74 V$ respectively. Which of the following orders regarding the reducing power of the metals is correct?