Question

How many amide isomers are possible for $C_4{H}_{9}ON$ ?

• A. 8
• B. 6
• C. 5
• D. 4

Answer 1

The correct option is A 8

For a compound with molecular formula $C_c{H}_h{X}_x{N}_n{O}_o$
$\text{Degree of unsaturation}=(c+1)-\frac{h}{2}-\frac{x}{2}+\frac{n}{2}$
Where, X = Halogen
c=number of carbon atom
h=number of hydrogen atom
n=number of nitrogen atom
o=number of oxygen atom
In $C_4{H}_{9}ON?$
$\text{Degree of unsaturation}=(4+1)-\frac{9}{2}+\frac{1}{2}=1$
Compound has one degree of unsaturation, it can be an amide as it contains one nitrogen and one oxygen atoms.
Hence, a total of 8 isomers are possible.