Question

How many banana bonds are there in Diborane?

Answer 1

The number of Banana bond present in Diborane:

• The structure of Diborane$\left({\mathrm{B}}_2{\mathrm{H}}_6\right)$ is formed by banana bonding. They are highly flammable, toxic and exothermic in nature.
• The electronic configuration of B is $1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^1$ indicates the atomic number is 5. In exited state, one of the $1s^{2}2s^{2}2p^1$valence electron $2\mathrm{s}$ get excited to $2\mathrm{p}$and form $s{p}^3$ hybridized orbitals. There are four hybrid orbitals one is empty and one has $3{\mathrm{e}}^{-}$.
• The B atom in $B_2{H}_6$ has two covalent bond. Thus, 2B forms $4$ covalent bond. Now, two B left with one empty orbital and one unpaired electron in each B atom. The bridge is formed between $\mathrm{B}-\mathrm{H}-\mathrm{B}$. These bonds are known as Banana bonds with the involvement of three atoms and one electron from Hydrogen and other from Boron, two electrons. A system of 3 atoms and 2 electron is formed.
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Thus, Diborane consist of two banana bonds.