How many gram ions of $S O_{4}^{2 -}$ are present in 1 gram molecule of $K_{2} S O_{4} . A l_{2} (S O_{4})_{3} . 24 H_{2} O$ ?

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 4
The total number of $S O_{4}^{2 -}$ ions present in 1 formula unit of $K_{2} S O_{4} . A l_{2} (S O_{4})_{3} . 24 H_{2} O = 4$

We know that ,one formula unit contains 1 mole of atoms, one gram ions equal to 1 mole

So, the total number of gram ions of $S O_{4}^{2 -}$ ions present in 1 gram molecule of $K_{2} S O_{4} . A l_{2} (S O_{4})_{3} . 24 H_{2} O = 4$

Suggest Corrections

Similar questions

S O_{4}^{2 -}

K_{2} S O_{4} . A l_{2} (S O_{4})_{3} . 24 H_{2} O

S O_{4}^{- 2}

K_{2} S O_{4} . A l_{2} (S O_{4})_{3} .24 H_{2} O

S O_{4}^{2 -}

K_{2} S O_{4} . A l_{2} (S O_{4})_{3} . 24 H_{2} O

S O_{4}^{2 -}

F e S O_{4} . (N H_{4})_{2} S O_{4} .6 H_{2} O

S O_{4}^{2 -}

F e S O_{4} . (N H_{4})_{2} S O_{4} .6 H_{2} O

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program