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Question
How many optically active stereoisomers are possible for butane-2,3-diol?
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Solution
Butane-2,3-diol:
CH3−CH(OH)−CH(OH)−CH3 has two chiral centers with same groups at the terminals.
Therefore, the compound will have 3 stereoisomers in which one has plane of symmetry and becomes optically inactive. The other two isomers are non-superimposable mirror images called enantiomers which are optically active.
Hence, number of optically active stereoisomers are 2.
Optically inactive isomer:
Optically active isomer :
CH3−CH(OH)−CH(OH)−CH3 has two chiral centers with same groups at the terminals.
Therefore, the compound will have 3 stereoisomers in which one has plane of symmetry and becomes optically inactive. The other two isomers are non-superimposable mirror images called enantiomers which are optically active.
Hence, number of optically active stereoisomers are 2.
Optically inactive isomer:
Optically active isomer :
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