Question 63

How much does $93 p^{2} - 55 p + 4$ exceed $13 p^{3} - 5 p^{2} + 17 p - 90 ?$

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Solution

Required expression is
$93 p^{2} - 55 p + 4 - (13 p^{3} - 5 p^{2} + 17 p - 90) = 93 p^{2} - 55 p + 4 - 13 p^{3} + 5 p^{2} - 17 p + 90$
On combining the like terms,
$= 93 p^{2} + 5 p^{2} - 55 p - 17 p + 4 + 90 - 13 p^{3} = 98 p^{2} - 72 p + 94 - 13 p^{3} = - 13 p^{3} + 98 p^{2} - 72 p + 94$
So, $93 p^{2} - 55 p + 4$ exceed $- 13 p^{3} + 98 p^{2} - 72 p + 94$ from $13 p^{3} - 5 p^{2} + 17 p - 90$

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