How to find the derivative of cosec2x?
Calculation of derivative:
Formula: ddx(cosec(x))=-cosec(x)cot(x)
Chain rule: ddx[f(x)]2=2f(x)ddxf(x)
That is
⇒ddx(cosec2x)=2cosec(x)ddx(cosec(x))[∵Chainrule]⇒ddx(cosec2x)=2cosec(x)(-cosec(x)cot(x))[∵Aboveformula]⇒ddx(cosec2x)=-2cosec2(x)cot(x)
Therefore, the derivative of cosec2x=-2cosec2(x)cot(x).
how to find the derivative of cosec x by the first principle method ?/