how to find the values here : 7ab\c=cc

Open in App

Solution

A, B, C are digits.

7AB = 700+ 10 A + B. Its value is between 700 and 799.

CC = 10 C + C = 11 C, C * CC = 11C²

Given 700+ 10 A + B = 11 C²
So 700 <= 11 C² <= 799
63 <= C² <= 72
Hence, C = 8.

So 11 C² = 11 8² = 704

Hence, B = 4, A = 0.

A =0, B = 4, C = 8

Suggest Corrections

Similar questions

How to find the values here: 6ab*4=27a72

∠ A = 90^{\circ} a n d A B = A C . F i n d ∠ B a n d ∠ C .

(7 a b c + b^{2}) (7 - b c) + c ({2 b}^{3} - 9 a b)

- 7 a b c

Join BYJU'S Learning Program