Hydrolysis of $P_{4} O_{10}$ gives:

H_{3} P O_{3}

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H_{3} P O_{4}

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H_{3} P O_{2}

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H P O_{3}

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Solution

The correct option is B $H_{3} P O_{4}$
Hydrolysis of $P_{4} O_{10}$ gives phosphoric acid.
$P_{4} O_{10} + 6 H_{2} O \to 4 H_{3} P O_{4}$

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