I. 2x + 3y = 4
II. 3x + 2y = 11

x < y

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\leq

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x = y

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\geq

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x > y

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Solution

The correct option is E x > y
Equation I
2x + 3y = 4 ...(i)
Equatoin II
3x + 2y = 11 ...(ii)
On multiplying Eq. (i) by 3 and Eq. (ii) by 2 and substracting Eq. (ii) from Eq. (i),
$6 x + 9 y = 12 6 x + 4 y = 22 - - - - ----------- - 5 y = - 10$
$∴ y = - 2$
On putting the value of y = - 2 in Eq. (i),
$2 x + 3 \times - (2) = 4$
Therefore, x>y

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