I -3 x 2-8 x -4-0II- 4 y 2-19 y -12-0A- if x-yB- if x - yC- if x-yD- if x - yE- if x-y or the relationship cannot be established

The correct option is C if x lt; y I. 3x^2+ 8x + 4 = 0 Or 3x^2+ 6x + 2x + 4 = 0 Or 3x (x + 2) + 2(x + 2) = 0 Or (3x + 2) (x + 2) = 0 Therefore x = 2/3 or ...

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Quantitative Aptitude

Equations

I .3 x 2+8 x ...

Question

$I . 3 x^{2} + 8 x + 4 = 0$

$I I . 4 y^{2} - 19 y + 12 = 0$

if x > y

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if x ≥ y

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if x < y

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if x ≤ y

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if x = y or the relationship cannot be established

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Solution

The correct option is C
if x < y

I. 3 $x^{2}$ + 8x + 4 = 0
Or 3 $x^{2}$ + 6x + 2x + 4 = 0
Or 3x (x + 2) + 2(x + 2) = 0
Or (3x + 2) (x + 2) = 0
Therefore x = $- \frac{2}{3}$ or -2
II. 4 $y^{2}$ - 19y + 12 = 0
Or 4 $y^{2}$ - 16y - 3y + 12 = 0
Or 4y (y - 4) - 3(y - 4) = 0
Or (4y - 3) (y - 4) = 0
Therefore y = $\frac{3}{4}$ or 4
So x < y is the answer.

Suggest Corrections

I.3x2+8x+4=0 II.4y2−19y+12=0

$I . 3 x^{2} + 8 x + 4 = 0$

$I I . 4 y^{2} - 19 y + 12 = 0$