CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Question 84 (i)

Simplify

(3x+2y)2+(3x2y)2

Open in App
Solution

We have
(3x+2y)2+(3x2y)2=(3x)2+(2y)2+2×3x×2y+(3x)2+(2y)22×3x×2y
[using the identities, (a+b)2=a2+b2+2ab and (ab)2=a2+b22ab]
=9x2+4y2+12xy+9x2+4y212xy=(9x2+9x2)+(4y2+4y2)+12xy12xy=18x2+8y2


flag
Suggest Corrections
thumbs-up
62
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon