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Question

(i) x2+y2+z2xy+x+yz by x+yz

(ii) x2+4y2+z2+2xy+xz2yz by x2yz

(iii) x2+4y2+2xy3x+6y+9 by x2y+3

(iv) 9x2+25y2+15xy+2x20y+16 by 3x5y+4

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Solution

(i)(x2+y2+z2xy+yz+zx)by(x+yz)x3+y3z3+3xyz(ii)(x2+4y2+z2+2xy+xz2yz)by(x2yz)=(x2yz)[x2+(2y)2+(z)2x×(2y)(2y)(z)(z)(x)]=x3+(2y)3+(z)33x(2y)(z)=x38y3z36xyz(iii)x2+4y2+2xy3x+6y+9byx2y+3=(x2y+3)(x2+4y2+9+2xy+5y3x)=(x)3+(2y)2+(3)33×x×(2y)×3=x38y3+27+18xy(iv)9x2+14y2+15xy+12x20y+16by3x5y+4=(3x5y+4)[(3x)2+(5y)2+(4)23x×(5y)(5y×4)(4×3x)]=(3x)3+(5y)3+(4)33×3x(5y)×4=27x3125y3+64+180xy


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