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Question

If 0x2π, 0y2π and sinx+siny=2, then the value of x+y is :

A
π
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B
π2
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C
3π
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D
None of these
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Solution

The correct option is A π

Given:

x,y[0,2π]

sinx+siny=2

We know that,

1sinx1

1siny1

Add both the above expressions.

2sinx+siny2

Therefore, if

sinx+siny=2

sinx=1

siny=1

Therefore,

x=π2 and y=π2

Therefore,

x+y=π2+π2=π

Hence, this is the required result.

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