If $2160 =$ $2^{a} \cdot 3^{b} \cdot 5^{c}$ , find a

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Solution

Given, $2160 = 2^{a} . 3^{b} . 5^{c}$
Now,
$2160 = 2^{4} . 3^{3} . 5^{1}$
Thus, comparing the above two, we get
$a = 4$ , $b = 3$ , $c = 1$ ,

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Similar questions

2160 = 2^{a} . 3^{b} . 5^{c}

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