If 2l−3m=−1 and lm=20, then the value of 4l2+9m2 is ________.
We know the identity a2+b2−2ab=(a−b)2
Given, 2l−3m=−1
Squaring on both sides, we get
(2l−3m)2=(−1)2
⇒4l2+9m2−12lm=1 .....Also given that lm=20
⇒4l2+9m2−12×20=1
⇒4l2+9m2−240=1
⇒4l2+9m2=241
Hence, option C is correct.