If 2x-3y=4, the value of 8x3-27y3-72xyis
32
16
128
64
Explanation for correct answer:
Using identities and finding the value of 8x3-27y3-72xy:
(Identity used a3-b3=(a-b)3+3ab(a-b)).
8x3-27y3-72xy=(2x)3-(3y)3-72xy
=(2x-3y)3+3×2x×3y×(2x-3y)-72xy
=43+3×2x×3y×4-72xy (∵Given 2x-3y=4)
=43+72xy-72xy
=43=64
Hence the correct answer is (D).
If 2x−3y = 10 and xy=16; find the value of 8x3−27y3
If 2x+3y=13 and xy=6 find the value of 8x3+27y3.