Question

If $2y+\frac{5}{3}=\frac{26}{3}-y$, then $y=?$

(a) $1$

(b) $\frac{2}{3}$

(c) $\frac{6}{5}$

(d) $\frac{7}{3}$

Answer 1

The correct option is (d) $\frac{7}{3}$

Given equation $2y+\frac{5}{3}=\frac{26}{3}-y$
$\Rightarrow 2y+y=\frac{26}{3}-\frac{5}{3}$ [Adding $y$ on both sides]
$\Rightarrow 3y=\frac{26-5}{3}\Rightarrow 3y=\frac{21}{3}\Rightarrow 3y=7$
$\Rightarrow \frac{3y}{3}=\frac{7}{3}$ [Dividing both sides by $3$]
$\Rightarrow y=\frac{7}{3}$
Therefore, the value of $y$ is $\frac{7}{3}$.